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15x^2-56x+49=0
a = 15; b = -56; c = +49;
Δ = b2-4ac
Δ = -562-4·15·49
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-14}{2*15}=\frac{42}{30} =1+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+14}{2*15}=\frac{70}{30} =2+1/3 $
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